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Simple Harmonic Oscillator

easy15 pts

Statement#

A mass mm is attached to a spring with spring constant kk and can move horizontally without friction. The spring obeys Hooke's law: F=kxF = -kx.

  1. Derive the equation of motion for the mass
  2. Solve the differential equation to find x(t)x(t), the position as a function of time
  3. Express the solution in terms of the angular frequency ω=k/m\omega = \sqrt{k/m}

Required Topics#

  • Newton's second law
  • Hooke's law
  • Second-order linear differential equations
  • Initial conditions
  • Simple harmonic motion

Given Information#

  • Mass: mm
  • Spring constant: kk
  • Restoring force: F=kxF = -kx (Hooke's law)
  • Initial position: x(0)=x0x(0) = x_0
  • Initial velocity: v(0)=v0v(0) = v_0

What to Find#

  1. The differential equation: md2xdt2+kx=0m\frac{d^2x}{dt^2} + kx = 0
  2. General solution: x(t)x(t) in terms of ω\omega, x0x_0, and v0v_0
  3. The period of oscillation TT

Solution#

Solution coming soon.

Hints (4)

Topics Needed

harmonic-oscillatordifferential-equationssprings

Prerequisites

  • newton-laws
  • basic-calculus

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